NHC

I think there are a number of tie breakers before that point.  1st round points, beard length, bribes to the GC, etc

;D

That’s true. I remember hearing that there were a dozen or so tiebreaking rules.

Yeah, I’m just not a fan of the machine gun tactic. Shotgun perhaps.  I think sending your six best is more than reasonable for a popular national competition with limited judging resources. 
Thanks AHA, looks like things are going pretty well this year so far.

Twenty way knife fight. That should happen on stage regardless of whether there is a tie. It’s just something people want to see.

If it does happen it will be over the Brewing Network winning the Homebrew Club of the Year.

Is this the homebrew equivalent to Godwin’s Rule?

With limited entries, one possible thought in regard to Ninkasi is make the first criteria the total number of medals won in the final round.  For instance if 2 people win 3 medals (of any color) they are the only two in contention.  To me, a silver and a bronze in the final (or even 2 bronzes) is more impressive than a single gold… if we are talking about Ninkasi.

By the time you are talking about medaling in the final round… they are ALL great beers.  If Ninkasi is about who can brew the greatest number of great beers… well, the first criteria should be who is winning the most medals.  From there, go with a point system.  That would make it less likely that there is the 23-way tie scenario.

Or, maybe incorporate points from both the first round and the second round right off the bat…

Just a thought - as entries are limited, it will become a case of a single gold possibly carrying enough weight to make the Ninkasi pretty crazy.

These are this year’s Ninkasi tiebreaker rules. Edit: 2 and 3 are identical. Typo?

  • The number of medals earned in the Final Round will be tallied, and the brewer with the most medals will be declared the winner. If a tie still exists,
  • The number of Gold medals earned in the Final Round will be tallied, and the brewer with the most Gold medals will be declared the winner. In case a tie still exists,
  • The number of Gold medals earned in the Final Round will be tallied, and the brewer with the most Gold medals will be declared the winner. In case a tie still exists,
  • The number of entries qualifying for the Final Round will be tallied for each tying brewer, and the brewer with the fewest entries in the Final Round will be declared the winner. In case a tie still exists,
  • Points will be calculated for tying brewers’ entries that placed in the First Round of the NHC based on the same scale as used in the Final Round. The brewer with the most points in the First Round will be declared the winner. If a tie still exists,
  • The number of entries qualifying for the Final Round will be tallied for each tying brewer, and the brewer with the most entries placing in the First Round will be declared the winner. In case a tie still exists,
  • The total number of entries registered for the First Round of the competition will be tallied for each tying brewer, and the brewer with the fewest registered entries will be declared the winner. If a tie still exists,
  • The winner will be selected using a random selection method. A random method such as rock-paper-scissors, steel cage death match, or a coin flip will be applied at the discretion of the competition organizers to determine the winner.

Mtnrockhopper just beat me to posting last years rules.  I wanted to note that some of the final rules were inspired by suggestions on this forum, proof that the AHA pays attention here

Hi all,

The tie-breaker rules for the Ninkasi Award are posted in the NHC Rules & Regulations (http://www.homebrewersassociation.org/competitions/national-homebrew-competition/rules-and-regulations/).  The tie-breaker criteria was expanded last year to account for the increased possibility of ties occurring.

Cheers,
Janis

I do remember ties even when there were no limits on entries. There was a 3 way tie in San Diego.

So there you go, tiebreakers were needed, and will be needed.

Honestly, I can’t figure out where #6 is going. It starts as a duplicate of 4 and then switches rounds.

I assume “C” should say “Silver”…or perhaps is just a typo that the same one was in there twice?
also, I still don’t understand why “d” and “f” are basically the opposite…I brought this up with Gary last year.

d) says fewest Final Round entries
f) says most First Round Entries placing, which = most Final Round entries

(f could instead say fewest First Round entries…just a thought.)

Final Round, the following tie-breaker criteria will apply.
a.The number of medals earned in the Final Round will be tallied, and the brewer with the most medals will be declared the winner. If a tie still exists,
b.The number of Gold medals earned in the Final Round will be tallied, and the brewer with the most Gold medals will be declared the winner. In case a tie still exists,
c.The number of Gold medals earned in the Final Round will be tallied, and the brewer with the most Gold medals will be declared the winner. In case a tie still exists,
d.The number of entries qualifying for the Final Round will be tallied for each tying brewer, and the brewer with the fewest entries in the Final Round will be declared the winner. In case a tie still exists,
e.Points will be calculated for tying brewers’ entries that placed in the First Round of the NHC based on the same scale as used in the Final Round. The brewer with the most points in the First Round will be declared the winner. If a tie still exists,
f.The number of entries qualifying for the Final Round will be tallied for each tying brewer, and the brewer with the most entries placing in the First Round will be declared the winner. In case a tie still exists,
g.The total number of entries registered for the First Round of the competition will be tallied for each tying brewer, and the brewer with the fewest registered entries will be declared the winner. If a tie still exists,
h.The winner will be selected using a random selection method. A random method such as rock-paper-scissors, steel cage death match, or a coin flip will be applied at the discretion of the competition organizers to determine the winner.

G is fewest first round entries, so it can’t be F too.

Right. If you’ve arrived at F, you’re guaranteed to get a tie because F = D and D is already a tie. This is going to drive me crazy.

Hi all,

Thanks for pointing out the repeated rule in the Ninkasi Tiebreaker.  That has been fixed.  Thanks.  The tiebreaker list was the result of the AHA Governing Committee Competition Subcommittee discussions following the 2012 National Homebrew Competition.

Cheers,
Janis

Oh dear lord, let’s not start this argument again!  :wink:

as always, your hard work is appreciated. 
…just my OCD showing up again.

cheers–
–Michael

As suggested I think the ‘argument’ will be settled this year with knives. lol

I’ll just point out that the last tiebreaker is…

g-  The winner will be selected using a random selection method. A random method such as rock-paper-scissors, steel cage death match, or a coin flip will be applied at the discretion of the competition organizers to determine the winner.

Better get that cage built for Grand Rapids.  I’m already training.