Not sure how to figure this one, so I thought I’d ask:
5 gallons of a 1.052 wort with 3 quarts water added = ? gravity
Thanks
Total Gravity points = (52*5) = 260
New Gravity points = (52*5)/5.75 gallons = 45.22
New SG = 1.045
Ahh. thank you Sir. Simple enough equation too.
Promash
C1V1 = C2V2
manipulate the equation to isolate the unknown and solve
C2 = C1V1/V2
where
C = concentration
V = volume
I get 7.033 when I do this. (1.052*20)/3
1.052 is a ratio. it must be expressed as a concentration → 52 points of gravity
(52*20)/3 = 346.67 points of gravity
1.347
if you take 20 gallons of beer with SG 1.052 and reduce the volume to three gallons the SG becomes 1.347
or conversly
if you take a concentrated wort boil of 3 gallons with SG 1.347 and dilute it to 20 gallons your OG would be 1.052
I get 45.2 when I do this. (52*20)/23
(You need to use a concentration measure (PPPPG) not SG
Plus you must account for the final volume of 23 qts
Oh, I see what you did euge - you converted gallons to quarts.
1.052 is the weight of the wort divided by the weight of water (a ratio)
And I did it wrong to C2 is 23 quarts? I see now drop the 1.0 from 1.052…
Yes, C2 is the total volume not the change in volume
and use points of gravity not the ratio.
Also, I misspoke - 1.052 is the density (mass per unit volume) of wort divided by the density of water. (a ratio)
Writing a 10-12 page paper on morality in war and then read this thread.
Pretty sure my head just explode from philosophy and math overload.
E=MC2
Where
E=Every Beer
M=Malt
C=Citrus Hops