Am I calculating the amount of Kmeta I am adding to rid the water of chlorine correctly?
I normally use distilled water and build from scratch therefore chlorine and chloramine are a non issue for me. However, the grocery has been unable to maintain a reliable stock of distilled water, I don’t operate a distillery, and I feel like those folks who require distilled water medically should get the limited supply on the shelves. So, that leaves me with New Market AL tap water.
Based on a photo of a package (link below), Campdem tablets = 550 mg KMeta which will treat 20 gal of chlorinated water. 550/20=27.5 mg per gallon. 1000 mg = 1 gram. So, .0275 grams per gal x 8.5 gal = .23 grams. I round up to .3
Edit: based on post #6 below, in retrospect I imagine rounding up was a mistake.